Developer (m/w)
Pubblicato il 15-08-2026 - Burberry in Italia
Founded in 1856 by Thomas Burberry, Burberry is a global luxury brand with a distinctly British attitude. We are a global business with an extensive network of both owned and franchised stores across EMEIA, Asia Pacific and Americas. We are digital pioneers, and innovative technology underpins every aspect of our business, from product design to distribution and marketing. We believe that modern luxury means being socially and environmentally responsible; JOB PURPOSE Burberry is looking for a skilled Trim Developer to support the research, development and delivery of trims across ready-to-wear collections. In this role you will playa vital part in translating creative vision into high-quality, commercially viable products, ensuring trims are developed in line with design intent, timelines and budget. Working collaboratively across Design, Product Development and Engineering, you will help bring innovation and craftsmanship to every detail. Lead seasonal trim research and present new concepts that align with design direction and brand standards.
Collaborate cross-functionally with Design, Product Development and Engineering teams to resolve technical challenges and support product testing. Maintain accurate and up-to-date information within PLM systems, ensuring consistency and transparency throughout development. Proven experience working with vendors, with the ability to communicate clearly and build effective partnerships. Confident managing multiple projects, balancing creativity with commercial awareness and cost considerations. Knowledge across areas such as fabrics, raw materials, garment construction and leather is highly valued. Effective communicator, comfortable influencing cross-functional teams and navigating challenges collaboratively. Experience with relevant systems and tools, including PLM and Microsoft Excel, with a detail-oriented approach to accuracy. FOOTER Burberry is an Equal Opportunities Employer and as such, treats all applications equally a